5.NBT.6: Divide by Two-Digit Divisors
Also written as 5.NBT.B.6 and CCSS.MATH.CONTENT.5.NBT.B.6 · Cluster: Perform operations with multi-digit whole numbers and with decimals to hundredths.
The Official Wording
Find whole-number quotients of whole numbers with up to four-digit dividends and two-digit divisors, using strategies based on place value, the properties of operations, and/or the relationship between multiplication and division. Illustrate and explain the calculation by using equations, rectangular arrays, and/or area models.
Common Core State Standards, Grade 5, Number & Operations in Base Ten · Read it at the source · Checked October 14, 2026
What 5.NBT.6 Means in Plain English
Fifth graders divide 1,587 ÷ 23 in chunks: 23 × 60 = 1,380 leaves 207, and 23 × 9 = 207 finishes it, so the quotient is 69. They show the thinking with equations or an area model, a rectangle 23 wide split into 60 and 9.
The standard algorithm for long division is not required until 6th grade (6.NS.2). This year is about place value: knowing 23 × 60 is 1,380 because 23 × 6 is 138, and seeing division as the reverse of multiplication (5.NBT.5). The same reasoning drives decimal division in 5.NBT.7.
5.NBT.6 I Can Statements
- I can divide a four-digit number by a two-digit number.
- I can use multiples of 10 of the divisor to divide in chunks.
- I can show my division with equations or an area model.
5.NBT.6 Worked Example
A four-digit dividend and a two-digit divisor, taken apart in chunks of the divisor, with the area model that shows why the chunks add up.
Divide 1,587 ÷ 23. Show the thinking with equations and an area model.
- Ask how many 23s fit. Use a friendly multiple: 23 × 10 = 230, so 23 × 100 = 2,300 is too big. Try tens.23 × 50 = 1,150, 23 × 60 = 1,380, 23 × 70 = 1,610 (too big)
- Take 60 groups of 23 out of 1,587 and see what is left.1,587 − 1,380 = 207
- How many 23s in 207? 23 × 9 = 207 exactly, so 9 more groups.207 − 207 = 0
- Add the partial quotients: 60 groups and 9 groups.60 + 9 = 69, so 1,587 ÷ 23 = 69
- As an area model: a rectangle 23 tall, split into a 60-wide piece (area 1,380) and a 9-wide piece (area 207). Total width 69, total area 1,587.23 × 60 + 23 × 9 = 23 × 69 = 1,587
Check it: Multiply back: 23 × 69 = 23 × 70 − 23 = 1,610 − 23 = 1,587. A quick estimate agrees too: 1,400 ÷ 20 is 70, close to 69.
Common Mistakes with 5.NBT.6
Guessing too small and never finishing
1,587 ÷ 23: take out 23 × 10 six times and 23 × 1 nine times, then lose track of the count
Try this: List the divisor’s multiples of 10 first (230, 460, 690, up to 1,380) so the first chunk is as large as it can be.
Subtracting the wrong amount
1,587 − 60 = 1,527 after deciding on 60 groups
Try this: Write the chunk as a multiplication equation before subtracting: 23 × 60 = 1,380, and 1,380 is what leaves the dividend, not 60.
Leaving a remainder bigger than the divisor
2,950 ÷ 34 = 85 R 60
Try this: Compare every remainder with the divisor. 60 is more than 34, so another 34 fits: 86 R 26.
Where 5.NBT.6 Fits
Practice 5.NBT.6
Quick Check
- 1,872 ÷ 24
- 3,416 ÷ 56
- A school has 1,250 pencils to pack into boxes of 36. How many full boxes, and how many pencils are left over?