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Common Core Math7th GradeGeometry

7.G.4: Area and Circumference of a Circle

Also written as 7.G.B.4 and CCSS.MATH.CONTENT.7.G.B.4 · Cluster: Solve real-life and mathematical problems involving angle measure, area, surface area, and volume.

The Official Wording

Know the formulas for the area and circumference of a circle and use them to solve problems; give an informal derivation of the relationship between the circumference and area of a circle.

Common Core State Standards, Grade 7, Geometry · Read it at the source · Checked October 14, 2026

What 7.G.4 Means in Plain English

Seventh graders use C = πd and A = πr², with 3.14 for π. A garden 10 ft across needs 31.4 ft of edging and covers 78.5 ft², and students can say which question asks for distance around and which asks for space inside.

They also explain why the formulas connect: cut a circle into thin wedges, lay them into a near-rectangle, and its area is half the circumference times the radius, which is πr². 8th grade builds cylinder and cone volume on πr² (8.G.9).

7.G.4 I Can Statements

  • I can find a circle’s circumference from its radius or diameter.
  • I can find a circle’s area using A = πr².
  • I can explain why rearranged wedges give the area formula.

7.G.4 Worked Example

A round garden bed: the edging is the circumference, the soil is the area, and a ring of wedges shows why the two formulas belong together.

Problem

A circular garden is 10 ft across. How many feet of edging go around it, and how much ground does it cover? Use 3.14 for π.

Edging and soil for a round garden
  1. Ten feet across is the diameter. The radius is half of it.r = 10 ÷ 2 = 5 ft
  2. Edging goes around the outside, so it is the circumference.C = πd = 3.14 × 10 = 31.4 ft
  3. Ground covered is area. Square the radius first, then multiply by π.A = πr² = 3.14 × 5² = 3.14 × 25 = 78.5 ft²
  4. Why πr² works: cut the circle into 16 thin wedges and lay them tip up, tip down. They make a near-rectangle as long as half the circumference and as tall as the radius.A ≈ ½C × r = 15.7 × 5 = 78.5 ft²
Answer31.4 ft of edging and 78.5 ft² of ground, using 3.14 for π

Check it: Box the circle in a 10 by 10 square, 100 ft²: the circle fills a little over ¾ of it, and 78.5 is. The edging is a little more than 3 diameters, 30 ft, and 31.4 is.

Common Mistakes with 7.G.4

Putting the diameter into πr²

A = 3.14 × 10² = 314 ft²

Try this: Halve the diameter first and write r = 5 above the formula; 314 ft² is the area of a circle 20 ft across.

Doubling the radius instead of squaring it

A = 3.14 × 5 × 2 = 31.4 ft²

Try this: Write r² as r × r, so 5 × 5 = 25, before multiplying by 3.14; doubling the radius gives the diameter, not its square.

Swapping area and circumference

A fence around a pen with a 5 ft radius is 78.5 ft long

Try this: Ask whether the answer is a length or a covering: fences and edging are circumference in feet, lawns and rugs are area in square feet.

Where 7.G.4 Fits

Practice 7.G.4

Word Problem GeneratorFree ToolStory problems about wheels, gardens and pizzas that make students choose between C = πd and A = πr² before calculating.GeometryCirclesGrade 7
Make Word Problems
Graph Paper GeneratorFree ToolTrace a circle of radius 5 cm on centimeter grid paper and count the squares inside, piecing partial ones together. About 78 squares backs up 3.14 × 25.1 cm squaresLetterPrint
Make Graph Paper

Quick Check

  1. A bike wheel has a diameter of 20 in. How far does it roll in one full turn? Use 3.14 for π.
  2. Find the area of a circle with a radius of 3 m. Use 3.14 for π.
  3. A circle’s circumference is 31.4 cm. What is its area? Use 3.14 for π.

7.G.4: Other Names

7.G.47.G.B.4CCSS.MATH.CONTENT.7.G.B.4

Common Core State Standards © Copyright 2010. National Governors Association Center for Best Practices and Council of Chief State School Officers. All rights reserved. Official wording from the Common Core State Standards PDFs at corestandards.org, last checked October 14, 2026. The explanation, I can statements, example, mistakes and practice on this page are EMStudio’s own, written beside the official wording. They are not part of the standard.