6.EE.5: Check Solutions by Substitution
Also written as 6.EE.B.5 and CCSS.MATH.CONTENT.6.EE.B.5 · Cluster: Reason about and solve one-variable equations and inequalities.
The Official Wording
Understand solving an equation or inequality as a process of answering a question: which values from a specified set, if any, make the equation or inequality true? Use substitution to determine whether a given number in a specified set makes an equation or inequality true.
Common Core State Standards, Grade 6, Expressions & Equations · Read it at the source · Checked October 14, 2026
What 6.EE.5 Means in Plain English
Sixth graders treat an equation as a question: which number makes it true? With x + 7 = 12 and candidates 3, 4 and 5, they substitute each. Only 5 + 7 = 12 works. For the inequality 2x < 9, two of the three pass, 3 and 4.
No solving method is required yet, and that is deliberate. The standard builds the meaning of “solution” before 6.EE.7 teaches the one-step moves and 6.EE.8 shows infinitely many solutions on a number line. The habit of checking by substitution pays off again with two-step equations in 7.EE.4.
6.EE.5 I Can Statements
- I can substitute a number into an equation to see if it is true.
- I can find which numbers in a set make an inequality true.
- I can explain what it means for a number to be a solution.
6.EE.5 Worked Example
A set of four candidates, one equation, and a plain yes or no for each after substituting.
Which number from the set {2, 4, 6, 8}, if any, makes 3x + 2 = 14 true?
- A solution is a number that makes the two sides equal. Test the candidates one at a time, starting with 2.3(2) + 2 = 8, and 8 ≠ 14
- Try 4. Multiply first, then add.3(4) + 2 = 14, true
- Keep going. The question asks about the whole set, and a set could hold more than one solution or none at all.3(6) + 2 = 20, and 3(8) + 2 = 26
- Only one candidate made a true statement.x = 4
Check it: Read the true statement back: 3 × 4 is 12, plus 2 is 14, the number on the other side. The other three gave 8, 20 and 26, none of them 14.
Common Mistakes with 6.EE.5
Stopping at the first hit
x² = 2x with {0, 2, 5}: “0 works, so the answer is 0”
Try this: Test every number in the set before answering. Here 2 works too (4 = 4), so the solution set is {0, 2}.
Substituting into one side only
For 2x + 1 = x + 7, test x = 3: 2(3) + 1 = 7, “so 3 works”
Try this: Evaluate both sides separately and compare: left side 7, right side 3 + 7 = 10. Not equal, so 3 is not a solution.
Treating the inequality like an equation
x + 3 < 10 with {5, 7, 9}: “only 7 makes it 10, so 7”
Try this: Ask whether each statement is true as written: 8 < 10 yes, 10 < 10 no, 12 < 10 no. Only 5 is a solution.
Where 6.EE.5 Fits
Practice 6.EE.5
Quick Check
- Is 9 a solution of 27 ÷ x = 3?
- Which numbers from {1, 3, 5, 7} make 4x - 2 < 15 true?
- Which number from {2, 3, 4} makes 5n + 4 = 19 true?