8.G.8: Distance Between Two Points
Also written as 8.G.B.8 and CCSS.MATH.CONTENT.8.G.B.8 · Cluster: Understand and apply the Pythagorean Theorem.
The Official Wording
Apply the Pythagorean Theorem to find the distance between two points in a coordinate system.
Common Core State Standards, Grade 8, Geometry · Read it at the source · Checked October 14, 2026
What 8.G.8 Means in Plain English
Eighth graders find the straight-line distance between two points by drawing a right triangle beneath it. From (1, 2) to (7, 10) the legs run 6 across and 8 up, so the distance is √(36 + 64) = √100 = 10 units.
No new formula is needed: the grid hands over the legs and the Pythagorean theorem does the rest, with negative coordinates counted carefully. High school turns the same move into the distance formula and uses it for perimeters and areas on the grid (HSG-GPE.7).
8.G.8 I Can Statements
- I can draw a right triangle with a segment as its hypotenuse.
- I can find leg lengths on a grid, even across an axis.
- I can find the distance between two points with the Pythagorean theorem.
8.G.8 Worked Example
Two points on opposite sides of both axes, where counting across zero is the step students slip on.
Find the distance between A(−2, 5) and B(3, −7).
- Plot both points and draw a right triangle with AB as its hypotenuse. Put the corner level with A and straight above B.right angle at C(3, 5)
- Horizontal leg: from x = −2 to x = 3. Crossing zero means 2 units to the axis plus 3 beyond it.AC = 3 − (−2) = 5
- Vertical leg: from y = 5 down to y = −7, across zero again.CB = 5 − (−7) = 12
- Use the Pythagorean theorem on the two legs.AB² = 5² + 12² = 25 + 144 = 169
- Take the square root.AB = √169 = 13 units
Check it: The distance must be longer than either leg and shorter than the two legs walked end to end: 12 < 13 < 17. Marking the segment on a strip of paper and laying it along the grid gives about 13 too.
Common Mistakes with 8.G.8
Subtracting across zero wrongly
From x = −2 to x = 3 counted as 3 − 2 = 1
Try this: Count the grid squares for the first few problems, and match the count to 3 − (−2) = 5.
Adding the legs instead of their squares
AB = 5 + 12 = 17 units
Try this: Trace the two legs, then the slanted segment, with a finger. Cutting across is shorter than walking both legs, so it cannot be 17.
Squaring a negative difference wrongly
(−12)² written as −144, so AB² = 25 − 144
Try this: Write each leg as a length, which is never negative, before squaring. A negative number squared is positive anyway: (−12)² = 144.
Where 8.G.8 Fits
Practice 8.G.8
Quick Check
- Find the distance between (0, 0) and (9, 12).
- Find the distance between (−4, 1) and (2, 9).
- Find the distance between (1, 1) and (4, 3), to the nearest tenth.